*1.Work from Days:*

If A can do a piece of work in *n* days, then A’s 1 day’s work =

2. *Days from Work: *

*If A’s 1 day’s work = , then A can finish the work in n days.
*

3. *Ratio:*

If A is thrice as good a workman as B, then:

Ratio of work done by A and B = 3 : 1.

Ratio of times taken by A and B to finish a work = 1 : 3.

## Trick

One simple technique is using days in denominator while solving questions. For example, A can do a job in 3 days and B can do the same job in 6 days. In how much time they can do the job together.

Examiner can set the question in opposite way and can ask you how much time A or B alone will take to complete the job. It is quite easy to calculate said question by putting values in equation we arrived in above question.

You need to understand one simple concept – If A can do a job in 10 day then in one day A can do 1/10th of job.

## Shortcut

Number of daysrequired to complete the work |
Work that can be done per day |
Efficiency in Percent |
---|---|---|

n | 1/n | 100/n |

1 | 1/1 | 100% |

2 | 1/2 | 50% |

3 | 1/3 | 33.33% |

4 | 1/4 | 25% |

5 | 1/5 | 20% |

6 | 1/6 | 16.66% |

7 | 1/7 | 14.28% |

8 | 1/8 | 12.5% |

9 | 1/9 | 11.11% |

10 | 1/10 | 10% |

11 | 1/11 | 9.09% |

### Now let’s solve questions with this trick

**Question –**A take 5 days to complete a job and B takes 10 days to complete the same job. In how much time they will complete the job together ?

**Solution –**A’s efficiency = 20%, B’s efficiency = 10%. If they work together they can do 30% of the job in a day. To complete the job they need 3.33 days.

**Question –**A is twice as efficient as B and can complete a job 30 days before B. In how much they can complete the job together ?

**Solution**– Let efficiency percentage as x

**Question**– A tank can be filled in 20 minutes. There is a leakage which can empty it in 60 minutes. In how many minutes tank can be filled?

**Solution**–

**Method 1**

⇒ Efficiency of filling pipe = 20 minutes = 1/3 hour = 300%

We need to deduct efficiency of leakage so final efficiency is 200%. We are taking 100% = 1 Hour as base so answer is 30 minutes.

**Method 2**

⇒ Efficiency of filling pipe = 100/20 = 5%

⇒ Efficiency of leakage pipe = 100/60 = 1.66%

⇒ Net filling efficiency = 3.33%

So tank can be filled in = 100/3.33% = 30 minutes

You can solve every time and work question with this trick. In above examples you can find even simple calculations. While in exams you can do these calculations mentally and save lots of time.

Comment below in case of any query.

**Question** – 4 men and 6 women working together can complete the work within 10 days. 3 men and 7 women working together will complete the same work within 8 days. In how many days 10 women will complete this work ?

**Solution –**Let number of men =x, number of women = y

So 10 women can complete the job in 100/20 = 5 days

**Question** – A and B together can complete a task in 20 days. B and C together can complete the same task in 30 days. A and C together can complete the same task in 30 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone?

**Solution –**

⇒ Efficiency of A and B = 1/20 per day = 5% per day ________________1

⇒ Efficiency of B and C = 1/30 per day = 3.33% per day______________2

⇒ Efficiency of C and A = 1/30 per day = 3.33% per day______________3Taking equation 2 and 3 together

⇒ B + C = 3.33% and C + A = 3.33%

⇒ C and 3.33% will be removed. Hence A = B

⇒ Efficiency of A = B = 5%/2 = 2.5% = 1/40

⇒ Efficiency of C = 3.33% – 2.5% = 0.833% = 1/120

⇒ A can do the job in 40 days and C can do the job in 120 days he they work alone.

⇒ Ratio of number of days in which A and C can complete the job 1:3.